This is a CyberSecurity course

I Need help with Class C

- Broadcast address for each subnet

- Valid Host

Class A and B are examples

When you've chosen a possible subnet mask for your network and need to determine the number of subnets, valid hosts and the broadeast addresses of a subnet that mask will provide, all you need to do is answer five simple questions: - How many subnets does the chosen subnet mask produce? - How many valid hosts per subnet are available? - What are the valid subnets? - What's the broadcast address of each subnet? - What are the valid hosts in each subnet? Network address =192.168.0.0/24 Subnet mask =255.255.255.0 Practice Example on Class B: 255.255.192.0(7/18) 172.16.0.0 = Network address (Class B default is /16 or 255.255.0 ) 255.255.192.0 = Subnet mask - Subnets? 2n2=4. - Hosts? 2n14-2 = 16382 - Valid subnets? 256-192=64, so 0,64, 128, 192. - Broadcast address for each subnet (always the number ight before the next subnet)? - Valid hosts (the numbers between the subnet number and the broadcast address)? The following table shows you the subnet, valid host, and broadcast address of the first four and last four subnets in the 255.255.255.252 Class C subnet: Practice Example on Class A: 255.255.0.0 (/16) 10.0.0.0 = Network address 255.255.0.0= Subnet mask -Subnets? 28=256. -Hosts? 2 2M162=65534. - Valid subnets? 256-255=1, so 0,1.2,3, ... , 255. - Broodcast address for each subnet (always the number night before the next subnet)? -Valid hosts (the numbers between the subnet number and the broadcast address)? The following table shows you the subnet, valid host, and broadcast address of the first four and last four subnets in the 255.255.255.252 Class C subnet: - Subnets? 240 is 11110000 in binary. 24=16. - Hosts? 4 host bits, or 242=14. - Valid subnets? 256240=16. Start at 0:0+16=16.16+16=32. 32+16=48.48+16=64.64+16=80.80+16=96.96+16=112.112+16=128.128+16=144.144+16=160.160+16=176.176+16=192.192+16=208.208+16=224.224+16=240. - Broadcast address for each subnet? - Valid hosts