This is a python code and then they ask to improve it$.$ so the code will be first then the question. from os import strerror

# Initialize $26$ counters for each Latin letter.

# Note: we've used a comprehension to do that.

counters $=\{$chr$($ch$)$: $0$ for ch in range$($ord$(\text{'}$a$\text{'}),$ ord$(\text{'}$z$\text{'})+1)\}$

file$\_$name $=$ input$("$Enter the name of the file to analyze: $")$

try:

file $=$ open$($file$\_$name, $"$rt$")$

for line in file:

for char in line:

# If it is a letter...

if char.isalpha$()$:

# $...$ we'll treat it as lower$-$case and update the appropriate counter.

counters$[$char$.$lower$()]+=1$

file.close$()$

# Let's output the counters.

for char in counters.keys$()$:

c $=$ counters$[$char$]$

if c $>0$:

print$($char$,\text{'}->\text{'},$ c$)$

except IOError as e:

print$("$I$/$O error occurred: $",$ strerror$($e$.$errno$))$ The previous code needs to be improved. It's okay, but it has to be better.

Your task is to make some amendments, which generate the following results:

the output histogram will be sorted based on the characters' frequency $($the bigger counter should be presented first$)$

the histogram should be sent to a file with the same name as the input one, but with the suffix $\text{'}.$hist' $($it should be concatenated to the original name$)$

Assuming that the input file contains just one line filled with:

cBabAa

samplefile.txt

the expected output should look as follows:

a $->3$

b $->2$

c $->1$

Output

Tip: Use a lambda to change the sort order.