Question: This is a question about limits.Use L'Hopital's rule to compute the following limits.limx01-cos(3x)sin2(3x)=limx2x3+x2-4x-4x2-x-2=limx0ln(1+x22)3x2=13
This is a question about limits.Use L'Hopital's rule to compute the following limits.limx01-cos(3x)sin2(3x)=limx2x3+x2-4x-4x2-x-2=limx0ln(1+x22)3x2=13
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