This is all in Python.

(1) Let L be a list and let T be a target. Write code to find the index of the second occurrence of T in the list. If there is no such occurrence,

print a message to that effect. Try doing 2 versions, one using the builtin list methods and one using your own loop(s).

(2) Write code to check if a list L is a "palindrome", i.e., it read the same from back to front or from front to back. This is easy with builtins, try it

with loops.