Question: This is for java please explain what you did Currently, you can determine if an item is in the list by invoking myList.contains(item). Pretend that

This is for java please explain what you did

Currently, you can determine if an item is in the list by invoking myList.contains(item). Pretend that ListInterfacedoes not have a contains method.

Write a complete method from the client perspective to accomplish the following task for a list of Strings.

The method header is:

public boolean listContains (ListInterface myList, String item)

Do not use the toArray() method.

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