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_1&question_num... e Com... Crime Map - Crim... FDLE - Sexual Off... mugshots.palmbe... Bb Forum: DQ4 - CC.. Reading Li Question Completion Status: Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Use either the traditional method or P-value method as indicated. Identify the null and alternative hypotheses, test statistic (indicate if t or z), critical value(s) (indicate type), P-value, conclusion about the null hypothesis (with reason), and state the final conclusion that addresses the original claim. In tests of a computer component, it is found that the mean time between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 10 modified components resulted in the following times (in hours) between failures. 518 548 561 523 536 499 538 557 528 563 At the 0.05 significance level, test the claim that for the modified components, the mean time between failures is greater than 520 hours. Give all numerical answers exactly or correct to 3 decimal places (as appropriate). Note: Fill in blanks for Null and Alternative Hypothesis as follows: Symbol for variable (p or Mu), then connector (=, =/=, , =) followed by numerical value. Ho: HI: Cunnort Note: Fill in blanks for Critical Value(s) as follows: Symbol for variable (t_alpha, z_alpha, t_alpha/2 or z_alpha/2), then the sign (+, -, or +/-), then numerical value (to 3 decimal places) Critical Value(s): Test Statistic (indicate t or z) followed by numerical value (to 3 decimal places): P-Value (to 3 decimal places): Conclusion about Null Hypothesis: Reason for Conclusion about Null Hypothesis: Final Conclusion (Fill in the appropriate words or phrases to complete sentence): There is evidence to the claim that the mean time between failures is greater than $20 hours. Show All X png UI Online - Doc_....pdf APR 28 Stv 9 4 W