This is the answer for the minimum velocity, $10\mathrm{.}03$m$/$s and its corresponding angle is $52\mathrm{.}02$ degrees

$.$ The following velocity is the velocity that can achieve the same height and distance with its own corresponding angle.

i$)$ Projectile Motion Calculation

a$)$ Given that the desired height $$ is $8$ meters and the horizontal distance d is $2$ meters, calculate the minimum launch velocity and launch angle required to achieve this trajectory.

b$)$ Write out an equation that contains the variables of launch velocity and launch angle that can reach the required height and distance.