This is using MATLAB.

P3 Drag on an object considering only a vertical drop follows the formula Given: \& DragForce DF, then at each ith time step Tstep, take clc, clear DF(1)=0; DF(i)=CdqSpeed2+CdlSpeed, And Speed must be updated to Vely(i) before it is used above. AND Vely (i+1)=Vely(i)+(DF(i)/Mass+g)Tstep. \&MasS =10;8kg s8g=9.8; \$Negative Gravity s6Cdq=0.2;%6N/(m/s)2 s6Cdl=0.4;s6NN/(m/s) sY =25;; snmeters \&Tstep =40.0e3; svely (1)=0; s. peed=Vely Using a for end loop with 101 points, find the 101 element vectors Vely and time with a time step of Tstep =0.04sec, print the two column vectors using an fprintf in the loop Note you will have to set the initial value of Vely(1) and Time(1) and you will want to change Speed = Vely at each iteration so that the drag force can be recalculated. And also using a table command (you may have to transpose T, Vely) at the end of the loop: sThen Plot Vely vs Time s. \&\% Problem 3 Solution Here