This must be done using MATLAB

3. Paratrooper (35%) An US Army paratrooper is dropped from a C130 airplane at a height of 500 m. After 5 s the chute opens. Let y(t) be the height of the paratrooper as a function of time. Following Newton's third law, the acceleration of the paratrooper (expressed as a second derivative of his/hers position) will be proportional to the forces acting on him/her (here the gravity force FG and the air drag FD: where m is the mass of the paratrooper, including his equipment. The gravity force can be expressed in terms of gravity acceleration g-9.81 m/s and the air drag force is proportional to the air density p 1.225 kg/m3 (assume it is constant throughout the fall), coefficient of friction cD, the reference area of the falling object (A), and the square of the velocity (here expressed as a first derivative of the position y(t) We can formulate the equation of motion of this falling paratrooper as follows FD(t) y(0)500 (0) 0, where FD(t) is a function of time, and depends whether the trooper's parachute is open (t 25 s) or not (t