Question: This Primal Min LPmin = 3 1 + 2 2 + 3 s . t . 1 + 2 + 3 4 2 3 2

This Primal Min LPmin=31+22+3s.t.1+2+342321+2+23=61,2,30 has dualmax=41+22+63s.t.1+331+2+3212+23110,20,3ursOprah says that Row0 of the optimal Primal tableau is:[1231213rhs110030316]But since the Primal is a Min, the dual is a max and so weRead=[123]=1as usual from the optimal tableau,When the primal is a min the values of dual optimalare still readable from row0 of the optimal tableau in the same way:is the value under; or the negative under; or, if needed, the value underafter deleting Big-M.(heremeans coefficients from; called itin Dual Theorem)(1) for convenience, written horizontally:[123]=[]This time we are checking that thisis dual feasible:(2) plugging into the first dual constraint, left side equals(3) Plugging into the second dual constraint, left side equals(4) Plugging into the third dual constraint, left side equals

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