This problem is for Pyhton language. Thank you.

1. Checkpoint 1: The concept of endianness plays an important role on your laptop (or any computer hardware architecture). Specifically, endianness dictates whether the most significant byte (i.e., "big-end") or least significant byte (i.e., "little-end) is stored as the first byte of the value being stored at a given address. Some architectures are big-endian (e.g., Motorola 68K), while other architectures are little-endian (e.g., x86 and its descendants) Start by typing in the code below. Attempt to understand what's happening in the given code as you type it in. Key to understanding this code is that an int data type in C is stored as four bytes #include #include int main() /* Insert your four bytes of ASCII for your secret message int z - 0xFFFFFFFF; /The 0x prefix above indicates a hexadecimal number / char c - (char *)&z; printf( "%c", *c++ ); printf( "%c", *c++); printf( "%c", *c++); printf( "kcln", * return EXIT_SUCCESS Compile and run this code, then replace the hexadecimal value of variable z with your own secret four-letter word. To do so, look up each letter in an ASCII table and convert them to their corresponding hexadecimal values. You can find an ASCII table at the following URL https://en.wikipedia.org/wiki/ASCIIHASCII_control_code_chart Based on your output, what is the endianness of your laptop