Question: This problem uses the same information from the previous problem (PERT 1 of 2). Therefore, the expected time and variance for each activity are the

This problem uses the same information from the

This problem uses the same information from the previous problem (PERT 1 of 2). Therefore, the expected time and variance for each activity are the same. Given the following information, what is the probability that this will be completed in 14 weeks or less? Time Units = Weeks Immediate Predecessor Activity (IP) a m b 2 3 4 B 3 6 9 1 9 co un D 7 9 A,B CD E 3 3 9 Z 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.5000 0.5040 0.50800.5120 0.5160 0.51990.5239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.2 0.5793 0.58320.58710.59100.5948 0.59870.6026 0.6064 0.6103 0.6141 0.3 0.61790.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.66640.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.71230.7157 0.7190 0.7224 0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454 0.7486 0.7517 0.7549 0.7 0.7580 0.7611 0.7642 0.76730.7704 0.77340.7764 0.7794 0.78230.7852 0.8 0.7881 0.79100.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 1.00.84130.8438 0.8461 0.8485 0.85080.8531 0.8554 0.8577 0.85990.8621 1.10.86430.8665 0.8686 0.87080.8729 0.87490.87700.8790 0.8810 0.8830

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