This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. If an arrow is shot upward on Mars with a speed of 55 m/s, its height in meters & seconds later is given by y = 55t - 1.86+2. Exercise (a) Find the average speed over the given time intervals. (i) [1, 2] (ii) [1, 1.5] (iii) [1, 1.1] (iv) [1, 1.01] (v) [1, 1.001] Step 1 Recall that the average speed between times ti and to is calculated using Vave y(+2) - y($1) t2 - $1 We are given that y = 55t - 1.86t2. Evaluating at t = 1, we have y(1) = 55(1) - 1.86(1)2 = 53.14. Thus, the average speed between times 1 and 1 + h is as follows. Vave = Y(1 + h) - y(1) (1 + h) - 1 - 155(1 + h) - 1.86(1 + h)2] - 53.14 51.28h - 1h2 h h, h=0