Question: This question is based on a circuit model as shown below. V=1.8 liters. Ca=0.01 1/mm Hg, Cv-0.25 1/mm Hg, R=20 mm Hg/(l/min) Starling's law
This question is based on a circuit model as shown below. V=1.8 liters. Ca=0.01 1/mm Hg, Cv-0.25 1/mm Hg, R=20 mm Hg/(l/min) Starling's law of the heart is best described by Pv=.042*Q+.27* Q Q>0 A)(5) Calculate Pa and Pv when Q=0 B)(15) Calculate steady state Q,Pv, and Pa Pa=V/(Ca+Cv) + R Q Cv/(Ca+Cv) Pv=V/(Ca+Cv)-R Q Ca/(Ca+Cv) Cv V=Va+Vv Pa=Va/Ca Pv=Vv/Cv Py # R Pa Ca
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