Question: This question is designed to be answered without a calculator. Using differentials, the approximate change in the value of f(x) = x2 + 4x -

 This question is designed to be answered without a calculator. Usingdifferentials, the approximate change in the value of f(x) = x2 +4x - 1 as x changes from 3 to 3.1 is 0.1.1. 10. 100. This question is designed to be answered without a

calculator. What is the relative maximum value of the function f(x) =-x3 + 6x2 - 9x 1? This question is designed to beanswered without a calculator. The linearization of fix} = $2 at x= % is L(x) = X 16x+ 12. 16X 132. 128x+ 32.

This question is designed to be answered without a calculator. Using differentials, the approximate change in the value of f(x) = x2 + 4x - 1 as x changes from 3 to 3.1 is 0.1. 1. 10. 100. This question is designed to be answered without a calculator. What is the relative maximum value of the function f(x) = -x3 + 6x2 - 9x 1? This question is designed to be answered without a calculator. The linearization of fix} = $2 at x = % is L(x) = X 16x+ 12. 16X 132. 128x+ 32. 'i28x+ 48. This question is designed to be answered without a calculator. Let f(x) = (x - 1)3(x + 1)3. What are the relative extreme values, if any, of the function? There is no relative minimum value and no relative maximum value. There is no relative minimum value and a relative maximum value of 0. There is a relative minimum value of 1 and no relative maximum value. There is a relative minimum value of 1 and a relative maximum value of 0

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