This question is from my calculus class. Thanks for your help.

1. d Show that (In kx) = yIn x, given that x > 0 and k > 0 is a real number. Compute the derivative of the natural log of kx. Begin by letting u = kx, and substituting u into the equation. -(In kx) =- Compute the derivative using the chain rule. dx -Inu = d dx Substitute kx back in for u where it appears in the equation. dy (In kx) = d dy (kx) d Compute the derivative - (kx), and then use the result to simplify the right side of the equation. dx (In kx) = d Compare the result of computing -(In kx) to the derivative d - In x. dx dx ( Inkx ) = ( x in x + k O B. The derivatives are equal. O c. (In kx) =k . =Inx O D. The relationship is impossible to determine with the given information