This question relates to solving a simple differential equation using matrix methods. The personal data can...

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This question relates to solving a simple differential equation using matrix methods. The personal data can be found on Moodle by running the MATLAB code. Using the details of a differential equation and associated boundary conditions provided here, you should determine the solution using matrix methods. Be sure to clearly annotate your solutions including graphs and diagrams where necessary. Figure Q2 presents a simply supported beam under a uniformly distributed load. The deflection of the beam can be computed with the: -x¹ + 2Lx³ - L³x) y(x) = A W 24EI W kN dy W dx m 24EI L (m) Figure Q2: simply supported beam Where x is the distance (m) from the left end, E is the modulus of elasticity kN (EQ1) m second moment of inertia (m¹), W is load and L is the length (m). The above (−4x³ + 6Lx² − [³) B equation can be differentiated to yield the slope of the downward deflection as a function of (x): (EQ2) discrete points xn = (n − 1)^x, n = 1,2, ...,5 (i.e.x。 = 0, x₁ = 44x). m² I is If y = 0 at x = 0, use this equation with Euler's method (i.e. Forward Finite Difference Approximation) (Ax = =) to compute the deflection from x=0 to L at five L 5-1 Δχ, Χ2 = 2Δχ, ..., ..., X5 = This question relates to solving a simple differential equation using matrix methods. The personal data can be found on Moodle by running the MATLAB code. Using the details of a differential equation and associated boundary conditions provided here, you should determine the solution using matrix methods. Be sure to clearly annotate your solutions including graphs and diagrams where necessary. Figure Q2 presents a simply supported beam under a uniformly distributed load. The deflection of the beam can be computed with the: -x¹ + 2Lx³ - L³x) y(x) = A W 24EI W kN dy W dx m 24EI L (m) Figure Q2: simply supported beam Where x is the distance (m) from the left end, E is the modulus of elasticity kN (EQ1) m second moment of inertia (m¹), W is load and L is the length (m). The above (−4x³ + 6Lx² − [³) B equation can be differentiated to yield the slope of the downward deflection as a function of (x): (EQ2) discrete points xn = (n − 1)^x, n = 1,2, ...,5 (i.e.x。 = 0, x₁ = 44x). m² I is If y = 0 at x = 0, use this equation with Euler's method (i.e. Forward Finite Difference Approximation) (Ax = =) to compute the deflection from x=0 to L at five L 5-1 Δχ, Χ2 = 2Δχ, ..., ..., X5 =