Question: This question will refer to a parallel-plate capacitor like the one pictured to the right. The capacitor in question has square plates with side length

This question will refer to a parallel-plate capacitor like the one pictured to the right. The capacitor in question has square plates with side length 1, which are separated by a distance of 0.1. The gap between the plates begins filled with air. a. What is the capacitance of this parallelplate capacitor in Farads? Show your work use formula Capacitance = A/(4pi*Kc*d) b. If this capacitor were hooked up to a battery with a voltage of 300, how much charge would accumulate on each plate? Show your work. c. If the battery were still connected to the capacitor plates but a conductive metal slab with a width of 0.25 was inserted into the capacitor gap, what would change about the capacitor? I.e., would the voltage change? The charge? Why

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