Question: This week in lab, we talked about using antidierentiation to go from acceleration to velocity, then to position, of an object moving under gravitational force.

 This week in lab, we talked about using antidierentiation to go
from acceleration to velocity, then to position, of an object moving under

This week in lab, we talked about using antidierentiation to go from acceleration to velocity, then to position, of an object moving under gravitational force. We used the following second order differential equation: m) = 9, where g is acceleration under gravity. 1. If a rock is thrown upward from a 100 meter cli with initial velocity 10 meters per second, nd how long it takes to hit the ground at the bottom of the cliff. Recall that g = 9.8 meters per second per second

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!