Three dimensions. Three point particles are fixed in place in an xyz coordinate system. Particle A$,$ at the origin, has mass mA$.$ Particle B$,$ at xyz coordinates $(2\mathrm{.}00$d$,1\mathrm{.}00$d$,2\mathrm{.}00$d$),$ has mass $2\mathrm{.}00$mg$,$ and particle C$,$ at coordinates $(-1\mathrm{.}00$d$,2\mathrm{.}00$d$,-3\mathrm{.}00$d$),$ has mass $3\mathrm{.}00$m$.$ A fourth particle D$,$ with mass $4\mathrm{.}00$m g$,$ is to be placed near the other particles. In terms of distance d$,$ at what

$($a$)$ x$,($b$)$ y$,$ and $($c$)$ z coordinate should D be placed so that the net gravitational force on A from B$.$ C$,$ and D is zero?