Question: Three forces A = (5.08. 90'), A = (10.08, 30), A, = (10.0/, 1503) accelerate an 15 kg mass. What is the net force acting

Three forces A = (5.08. 90'), A = (10.08, 30), A, = (10.0/, 1503) accelerate an 15 kg mass. What is the net force acting on the mass? What is the magnitude and direction of the mass's acceleration? V 150 X 2. If a block with weight 250N is at rest on a horizontal surface. A vertically upward force is applied to the block. Calculate the magnitude and direction of force on the block generated from the horizontal surface if the applied vertically upward force F is (a) 100 N, (b) 250 N. 3. A man is pulling a string with a constant force of 1.ON. The string is attached to a toy on a frictionless surface. The string makes a 45" angle with the horizontal. The toy has a mass of 0.25 kg. Find the acceleration of the toy. 45
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
