Question: Three soldiers (named A, B, and C) must decide between themselves, which one goes on a dangerous mission. They decide to take turns drawing straws;

Three soldiers (named A, B, and C) must decide between themselves, which one goes on a dangerous mission. They decide to take turns drawing straws; there are 5 long straws and 1 short straw. Whoever picks the short straw must go on the mission. Soldier A picks first, soldier B picks second and soldier C picks third. On each draw soldier A will always draw 1 straw, soldier B will always draw 2 straws, and soldier C will always draw 3 straws. For each soldier (A, B, C) what is the probability they end up drawing the short straw?

1) Without replacement

2) WIth replacement

PAY ATTENTION:

1) Show me your work! Process! not just result

2) Claim question again "A will always draw 1 straw, soldier B will always draw 2 straws, and soldier C will always draw 3 straws. " means A took just 1 straw, B took 2 draws (not the second straw) C took 3 draws ( not the third straw)

3) Please read carefully and give me a nice answer or you wont get a helpful vote thx!

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