Time$($days$)$

Immediate

Time$($days$)$

Immediate

Activity

a

m

b

$$Predecessor$($s$)$

Activity

a

m

b

$$Predecessor$($s$)$

A

$4$

$6$

$7$

long dash

H

$4$

$4$

$6$

$$E$,$ F

B

$1$

$2$

$3$

long dash

I

$1$

$6$

$8$

$$G$,$ H

C

$6$

$6$

$6$

A

J

$2$

$5$

$7$

I

D

$5$

$8$

$11$

A

K

$8$

$9$

$11$

I

E

$1$

$9$

$18$

$$B$,$ C

L

$2$

$4$

$6$

J

F

$2$

$3$

$6$

D

M

$1$

$2$

$3$

K

G

$1$

$7$

$8$

D

N

$6$

$8$

$10$

$$L$,$ M

Part $2$

$$a$)$ The expected completion time of the project$=$

$$

enter your response here days $($round your response to two decimal$$ places$).$

Part $3$

The activities that represent the$$ project's critical path are

$$

A $-$ C $-$ E $-$ H $-$ I $-$ K $-$ M $-$ N

B $-$ E $-$ H $-$ I $-$ J $-$ L $-$ N

B $-$ E $-$ H $-$ I $-$ K $-$ M $-$ N

A $-$ D $-$ F $-$ H $-$ I $-$ K $-$ M $-$ N

A $-$ D $-$ F $-$ H $-$ I $-$ J $-$ L $-$ N

A $-$ C $-$ E $-$ H $-$ I $-$ J $-$ L $-$ N

A $-$ D $-$ G $-$ I $-$ J $-$ L $-$ N

A $-$ D $-$ G $-$ I $-$ K $-$ M $-$ N

$.$

Part $4$

$$b$)$ If the time to complete the activities on the critical path is normally$$ distributed, then the probability that the critical path will be finished in $53$ days or less$=$

$$

enter your response here $($round your response to two decimal$$ places$).$

Part $5$

$$c$)$ Using the standard normal tableLOADING...$,$ the number of days that would result in$99\%$ probability of completion$=$

$$

enter your response here days $($round your response to two decimal$$ places$).$