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Minimum cost =50X1+10X2+75X3
subject to
X1 X2=1,000
2X2+2X3=2,000
X1<=1,500
Solve the problem by the simplex method. Provide only the value of the basic variables at tableau #3.
Notes:
Set M =100.
Tableau #1 is the initial tableau where an inconsistency exists on row z.
Tableau #2 is the tableau where the inconsistency on row z is fixed.
Select one:
X1=1000, X3=2000, s1=0
X3=1000, X1=2150, X2=1500
X1=1000, X3=1000, s1=500
A1=1000, A2=2000, s1=1500
None of the options provided

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