Question: To break E.coli cells, it was found that operating a high-pressure homogenizer at 60 MPa had the following breaking percentages for each pass. Consider that

To break E.coli cells, it was found that operating a high-pressure homogenizer at 60 MPa had the following breaking percentages for each pass. Consider that the resistance of cells to break ()=2.2

number of passes % released protein
1 50.3
2 75.3
5 96.9
9 99.8

a) Determine the value of k from the rupture kinetics in the homogenizer as a function of the number of passes (N) and the pressure (P).

b) If you want to operate the same equipment at 65 MPa and break 98% of the cells, how many passes are required?

c) What pressure is required to break the same 98% of the cells in just two passes?

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!