To easily calculate E = EdAcos, (1) the closed surface must be taken to be a sphere of radius R and (2) the +q point charge must be placed at its center. Which one of the following is wrong? Question 20 options: E = EdAcos because the magnitude E is the same at all points of the sphere if +q is placed at the center. E = EdAcos = EdA because E and n become parallel at all points on the sphere that means =0 at all points. E = EdA = [kq/R2]dA = [kq/R2](4R2) = 4kq where 4R2 is the area of the sphere. E = EdA = [kq/R2]dA = [kq/R2](R2) = kq where R2 is the area of a circle