To evaluate one first makes the substitution u- This reduces the problem to integrating the polynomial...

 

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To evaluate one first makes the substitution u- This reduces the problem to integrating the polynomial P(u)=[ The general antiderivative P(u) du= In terms of the original variable , this antiderivative can be expressed as [ cosº (a) sin³ (2) da, To evaluate one first makes the substitution u- This reduces the problem to integrating the polynomial P(u)=[ The general antiderivative P(u) du= In terms of the original variable , this antiderivative can be expressed as [ cosº (a) sin³ (2) da,

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To evaluate cosx sinx dx We can use the substitution ... View the full answer