To find the surface area of the surface generated by revolving the curve defined by the...

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To find the surface area of the surface generated by revolving the curve defined by the parametric equations x=3t+2t, y=t, 1≤t≤6 around the z-axis you'd have to compute where a 1 b= 6 and f(t) = L' f(t)dt To find the surface area of the surface generated by revolving the curve defined by the parametric equations x=3t+2t, y=t, 1≤t≤6 around the z-axis you'd have to compute where a 1 b= 6 and f(t) = L' f(t)dt

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Sol Let x ft 31 2 and 424 Y gt t 1 t6 Then 3 1 121 2 ... View the full answer