To implement $[$a$],$ the TCP protocol uses "slow start" and an "additive$-$ increase $/$ multiplicative decrease" adaptive transmission algorithm. reliable data transmission none of these O congestion control connection$-$oriented service flow control A host starts a TCP transmission with an EstimatedRTT of $12$ms $($from the "handshake"$).$ The host then sends $3$ packets and records the RTT for each: SampleRTT$1=17\mathrm{.}8$ ms SampleRTT$2=17\mathrm{.}2$ ms SampleRTT$3=44\mathrm{.}9$ ms $($NOTE: SampleRTT$1$ is the "oldest"; SampleRTT$3$ is the most recent.$)$ Using an exponential weighted moving average with a weight of $0\mathrm{.}4$ given to the most recent sample, what is the EstimatedRTT for packet #$4?$ Give answer in miliseconds, rounded to one decimal place, without units, so for an answer of $0\mathrm{.}01146$ seconds, you would enter $"11\mathrm{.}5"$ without the quotes. What is the netmask of this IPv$4$ CIDR address: $128\mathrm{.}35\mathrm{.}185\mathrm{.}125/24128\mathrm{.}35\mathrm{.}184\mathrm{.}0255\mathrm{.}255\mathrm{.}255\mathrm{.}0$ none of these $128\mathrm{.}35\mathrm{.}3\mathrm{.}255255\mathrm{.}255\mathrm{.}252\mathrm{.}0$ What is the network address for this IPv$4$ CIDR address: $128\mathrm{.}35\mathrm{.}185\mathrm{.}125/24$ none of these $128\mathrm{.}35\mathrm{.}183\mathrm{.}0/24128\mathrm{.}35\mathrm{.}0\mathrm{.}0/24128\mathrm{.}35\mathrm{.}185\mathrm{.}0/24128\mathrm{.}35\mathrm{.}184\mathrm{.}0/24$ What is the range of possible host addresses generally accepted in the same network as this IPv$4$ CIDR address: $128\mathrm{.}35\mathrm{.}185\mathrm{.}125/24128\mathrm{.}35\mathrm{.}184\mathrm{.}1/24-128\mathrm{.}35\mathrm{.}187\mathrm{.}254/24128\mathrm{.}35\mathrm{.}185\mathrm{.}1/24-128\mathrm{.}35\mathrm{.}185\mathrm{.}254/24128\mathrm{.}35\mathrm{.}180\mathrm{.}1/24-1288\mathrm{.}254/24$ none of these $128\mathrm{.}35\mathrm{.}185\mathrm{.}0/24-128\mathrm{.}35\mathrm{.}185\mathrm{.}255/24$