Question: To prove equalities are correct, n 1.001 + n log n = Theta(n 1.001 ) 10n 3 + 15n 4 + 100n 2 * 2

To prove equalities are correct,

n1.001 + n log n = Theta(n1.001)

10n3 + 15n4 + 100n2 * 2n = O(100n2 * 2n)

To prove equalities are incorrect,

n3 * 2n + 6n2 * 3n = O(n3 * 2n)

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