Question: To solve this, let s use the given data step by step: - - - ### Part ( a ) : Flow Speed in Arterioles

To solve this, lets use the given data step by step:
---
### Part (a): Flow Speed in Arterioles
The formula for flow speed is:
\[
v =\frac{Q}{A}
\]
Where:
-\( Q \) is the volumetric flow rate (\(5.0\,\text{L/min}=5000\,\text{cm}^3/\text{min}\)),
-\( A \) is the total cross-sectional area (\(500\,\text{cm}^2\) for arterioles).
\[
v =\frac{5000\,\text{cm}^3/\text{min}}{500\,\text{cm}^2}
\]
---
### Part (b): Pressure Difference Across a 1.0 cm Length of the Arteriole
The pressure difference (\(\Delta P \)) can be determined using Poiseuille's law:
\[
\Delta P =\frac{8\mu L Q}{\pi r^4}
\]
Where:
-\(\mu \) is the viscosity of blood (\(\mu \approx 0.035\,\text{Poise}=0.035\,\text{g}/\text{cms}\)),
-\( L =1.0\,\text{cm}\) is the length,
-\( Q =5000\,\text{cm}^3/\text{min}=\frac{5000}{60}\,\text{cm}^3/\text{s}\),
-\( r =\frac{\text{diameter}}{2}=0.001\,\text{cm}\).
Plug these into the equation.
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Let me calculate these values for you.
### Solutions:
**(a) Flow speed in the arterioles:**
-\(10.0\,\text{cm/min}\) or \(0.167\,\text{cm/s}\).
**(b) Pressure difference across a 1.0 cm length of the arteriole:**
-\(7.43\times 10^{12}\,\text{dynes/cm}^2\), which is extraordinarily large. This suggests either a mistake in assumptions or unrealistic parameters (e.g., very small radius causing a high result).
Would you like clarification or adjustments based on alternate assumptions?

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