Toggle Sidebar

New

Agent

Hotel Double Cross Akshay words for the Socret Intelligent Servics His role involves decoding cryptic information Recently he has received $3$ sets of numbers $($ arrays of numbers$).$ The number of elements in vach set in each array$)$ is the same. These numbers have to be decoded to find the room number of a person staying in Hotel Double Cross. The below example demonstrates the steps to be performed while decoding the given numbers

Example $-$ Let us assume that the $3$ set of numbers are as below

input$1(1,2,3,4)$

input$2(2345)$

input$3(1\mathrm{.}3\mathrm{.}5\mathrm{.}7$

Step $1$: Generate a new set of elements by adding numbers present at the same index in the three

armays. So$,$ we get, $(4,112,16)$ Step $2.$ The array generated in step $1$ represents the position of the elements in the three arrays

Le

the first number $4$ represents the number in $4$th position in the FIRST array

the second number $8$ represents the number in $8$th position in the SECOND array. the third number $12$ represents the number in $12$th position in the THIRD array.

the fourth number $16$ represents the number in $16$th position in the FIRST array.

In STEP$2,$ our task is to pick the numbers from these specified positions from the respective

arrays. Le$.$

Number at $4$th position in the FIRST array is $4$

Number at $8$th position in the SECOND array is $5($Note that the array contains only $4$ elements, so the $8$th position can be found by counting the positions in cyclic manner, ie$,$ after reaching last element of the array, continue counting from the first element of the array. This way the number in the $8$th position in the second array is $5)$

Number at $12$th position in the THIRD array is $7($apply same counting logic as above$)$ Number at $16$th position in the FIRST array is $4($apply same counting logic as above$)$

So$,$ we get the positional numbers as $(4,5,7,4)$

Step $3$: Add ALL the positional numbers generated in step $2$ to get the FINAL Result which represents the room number in Hotel Double Cross. i$.$e$.$ Room number $=4+5+7+420$

Note:

There will always be THREE input arrays

All $3$ arrays will have the same number of elements

The number of array elements is specified by input$4$

The array elements will always be positive numbers greater than $0$ Note:

There will always be THREE input arrays

All $3$ arrays will have the same number of elements

The number of array elements is specified by input$4$

The array elements will always be positive numbers greater than $0$

input$1(10,33,5,40,120,98,1)$ input$2(121,78,21,32,91,340,72)$

Example $2$: Let us now assume the $3$ input arrays are as given below:

input$3(65,320,72,84,32,843,40)$ input$47($the number of elements in each of the input arrays$)$

Step$1$: The new set of elements by adding numbers present at the same index in the three arrays will be $(196,431,98,156,243,1281,113)$

$1($number present at position $196$ in input$1)$

Step$2$: Picking up numbers from input$1,$ input$2$ and input$3$ based on the output of Step$1$ we get:

$32($number present at position $431$ in input$2)$

$40($number present at position $98$ in input$3)$

$33($number present at position $156$ in input$1)$

$91($number present at position $243$ in input$2)$

$40($number present at position $1281$ in input$3)$

$10($number present at position $113$ in input$1)$

Step$3$: Sum of these numbers gives the Room Number: $247$

Author: Pranam Kaushik

Here is the incomplete Java code please give total code:

import java.io$.*$;

import java.util.$*$;

$//$ Read only region start

class UserMainCode

$\{$

public int findRoomNo$($int input$1,$ int input$2,$ int input$3,$ int input$4)\{$

$//$ Read only region end

$10$

$//$ Write code here...

$11$

$12$

$\}$

$13$

$\}$