Topic: Cache Memory: Direct Mapping:

$6$ A: General Size Parameters

Express these values as powers of $2.$

$-$ Main RAM size: $4$ Giga Byte $(4$GB$)=$

Block size: $64$ bytes $=$

Cache size: $2$ Mega Bytes$(2$MB$)=$

B: Refer to sizes of RAM and Cache mentioned in A above using Direct Mapping:

$-$Main Memory$/$ P$.$A RAM address bits size:$($ how many total bits required to address such size RAM$)$

$-$Total How many number of Blocks in Main memory RAM :

$-$ Total How many number of Blocks in Cache:

$-$ Show address bits breakdown: like $\backslash$#of Tag bits, $\backslash$# of Index bits, $\backslash$# of Block offset bits:

$7$ C: In a Direct Mapping Installed RAM: $16$ GB $($gigabytes$),$ Total cache: $8$ MB $($megabytes$),\backslash (\backslash$cdot $\backslash )$ Size of Block: $128$ Bytes

$-$ Show address bits breakdown: like $\backslash$#of Tag bits, $\backslash$# of Index bits, $\backslash$# of Block offset bits: