Topic: Conservation of Charge

Pls provide complete solution.

MINITASK #2. Solve the problem below. Sphere A has a charge of +10.o C. It is brought in contact with a neutral sphere B and then separated. Find the final charges on spheres A and B if a. the spheres have equal radius and b. if the radius of sphere B is twice the radius of sphere Ab. Let rA and IB represents the radius of spheres A and B, respectively. Therefore, TB = 2rA. the charge acquired by each sphere is directly proportional to their radius. Recall that if two quantities will have constant ratio if they are directly proportional. qA / TA = qB / IB qA / TA = 9b / 2rA qB = 29A but according to the principle of conservation of charge, qA + qB = +6.0 C qA + 29A = +6.0 C Therefore, qA = +2.0 C and qB = +4.0 CSample Problems: Metal sphere A has a charge of +6.0 C. It is brought in contact with a neutral metal sphere B and then separated. Find the final charges on spheres A and B if a. the spheres have equal radius and b. if the radius of sphere B is twice the radius of sphere A Solution: a. Since the spheres A and B are identical, they will be sharing the total charge. Therefore, after contact, qa = qb = +3.0 C