Translate the following C statement into an assembly program, assuming 16-bit signed integers x, y and z (i.e. signed short) are stored in 32-bit registers r0, rl, and r2, respectively. x=x*y+z-x; Translate the following C statement into an assembly program, assuming 16-bit unsigned integers x and y (i.e. unsigned short) are stored in registers r0, and rl, respectively. x=x%y