Question: True. If f ( n ) = ( g ( n ) ) f ( n ) = theta ( g ( n )

True. If f(n)=(g(n))f(n)=\theta(g(n))f(n)=(g(n)), then both f(n)=(g(n))f(n)=\Omega(g(n))f(n)=(g(n)) and f(n)=O(g(n))f(n)= O(g(n))f(n)=O(g(n)) hold by definition.

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