Try to use $h={10}^{-16}$ to approxmate the derivative. Display the value, and write a comment about what is happening. Why do you think this happened?

def f$($x$)$:

y$=$x$**2$

return y

x$=2$

h$=1$e$-16$

deriv$=($f$($x$+$h$)-$f$($x$))/$h

print$("$x $=",$ x$,"$h $=",$h$,$"derivative $=",$deriv$)$

x $=2$ h $=1$e$-16$ derivative $=0\mathrm{.}0$