TUMEWORK: Homework2 - Chapter 2 core: 0 of 3 pts 4 of 11 (17 complete HW Score: 92.5%, 37 of 40 pts x 2.2.19 Ona operation of a mais to cut pieces of time parts at will star be used as the frame for front seats in an automobile. These out with a diamonds and requests be win 10.00 hored by the automobile company Data were collected from a sample of 50 parts and are shown in the following te. The measurement reported is the difference in inchesten the actingh of reported by measurement device, and the specified length of the stolpert. For the first value 0.000, representer that is 0.002 nchthorter than the off complet portal Ciche con to view the dots att Constructancy distribution Difference in Length Frequency -0.005 bless than -0.003 -0.003 bulloss than -0001 -0.001 But no 001 0.001 bolless than 0.003 0.003 but less than 0.005 of 50 steel parts and are shown in the following table. The measurement reported is the difference in inches between the actual length of the art. For example, the first value, -0.002, represents a steel part that is 0.002 inch shorter than the specified length. Complete parts a through - i Difference Between Actual and Specified Lengths X -0.002 0.000 0.0015 0.002 -0.0015 -0.002 0.001 -0.0005 0.002 0.001 0.001 0.001 -0.002 -0.001 0.001 -0.001 0.0015 0.002 0.0015 0.001 0.002 0 -0.002 0 0.0015 0.001 -0.004 -0.003 0.003 0.001 Full data set -0.0 0.001 -0.001 0.0015 0.0035 -0.0015 -0.0015 -0.0015 0 -0.0035 0.0025 0 0 -0.0035 0 -0.0025 -0.001 0.0015 Print Done Check Answer Clear All