Tutorial Exercise Find the equation of the line through the point (4, 7) that cuts off the least area from the first quadrant. Step 1 A line with slope /m through (4, 7) has equation y = mx + 7-4m 7-m (Hint: Solve for b.) (x, y) Step 2 The y-intercept is 7-4m and the x-intercept is m Step 3 Therefore, the area to be minimized is given by A(m) (7-4m)(+4) Step 4 49 -28- 8 m 2m Now, A(m)= Step 5 49 22 2 Since m is negative, then solving 40 gives m -- Step 6 So the equation of the line which minimizes the area is Sub Skip you cannot come back)