Tutorial ExerciseUse Stokes' Theorem to evaluateCF drwhere C is oriented counterclockwise as viewed from above.F(x, y, z)=(x + y2)i +(y + z2)j +(z + x2)k,C is the triangle with vertices(2,0,0),(0,2,0), and (0,0,2).Step 1Stokes' Theorem tells us that if C is the boundary curve of a surface S, thenF drC=Scurl F dS.Since C is the triangle with vertices (2,0,0),(0,2,0), and (0,0,2), then we will take S to be the triangular region enclosed by C. The equation of the plane containing these three points isz =(1)x +(1)y +22.Step 2S is the portion of the plane z =2 x y which lies over the region D in the xy-plane, where D is bounded by the x-axis, the y-axis, and the liney =(1)x +22.Step 3ForF(x, y, z)=(x + y2)i +(y + z2)j +(z + x2)k,we havecurl F =$$i +$$j +$$k.Step 4Therefore, we have the following.F drC=curl F dSS=(2z)(1)(2x)(1)+(2y)(1)dAD=00dy dx