Question: TV 4 1 sin5 x dx 0 At first I divided sin5 x dx to sin4 x sin x dx And I changed sin x

 TV 4 1 sin5 x dx 0 At first I divided
sin5 x dx to sin4 x sin x dx And I changed

TV 4 1 sin5 x dx 0 At first I divided sin5 x dx to sin4 x sin x dx And I changed sin x to 1 cos x in terms of the Cosine function After that I solved it by using integral rules But I couldn t solve it Can anyone give me a hint to solve it I attached my calculations below

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