Two capacitors (air filled) are connected with a battery as shown above. Use C= 50 mF, C =100 mF, and AV = 12 V to solve the following questions: A. The total (equivalent capacitance) of this capacitor circuit is 150 B. The potential difference across capacitors C is [Select] mF. V and across C2 is [Select] V. C. The charge stored in capacitor C is [Select] [Select] C and in capacitor C is D. The total energy stored in this capacitor combination is [Select] E. Now, for this part, if C1 and C2 capacitors (values provided above) are now connected in series as shown below, then the total capacitance of the capacitors will be [Select] stored on each capacitor plate will be (closest to) [Select] mF, and the charge C. AV- HE D. The total energy stored in this capacitor combination is [Select] J. E. Now, for this part, if C1 and C2 capacitors (values provided above) are now connected in series as shown below, then the total capacitance of the capacitors will be [Select] stored on each capacitor plate will be (closest to) [Select] mF, and the charge C. C AV F. If a dielectric material of dielectric constant K = 3.2 is inserted between the plates of these air filled capacitors, the new capacitance of these capacitors will now be: Cinew = [Select] mF and C2new= [Select] mF.