Two cylinders $($ A and $B)$ at the same pressure and contain the same gas. If $B$ has half the volume and twice the number of moles as $A,$ how does the temperature in $B$ compare with the temperature in $A?$

$T_B=\frac{1}{4}{T}_A$

$T_B=\frac{1}{2}{T}_A$

$T_B=4T_A$

$T_B=T_A$

$T_B=2T_A$