Two equal masses are situated on the $x$ axis at $40\mathrm{.}0$ m on either side of the origin as shown in the figure below. Location A is on the perpendicular bisector at a distance of $26\mathrm{.}0$ m from the origin on the $y$ axis.

$($a$)$ If $m_1=4\mathrm{.}00kg$ and $m_2=4\mathrm{.}00kg,$ what is the net gravitational field due to both masses at location A$?$ Express your answer in vector form.

vec$(g{)}_{\text{n}\text{e}\text{t}}=$

$$

Did you consider the symmetry of the situation? What is the net contribution to the field from the $x$ components of the field from each mass? $\frac{m}{s^2}$

$($b$)$ If $m_1=4m_2,$ what is the net gravitational field at location A due to both masses? Express your answer in vector form. $($Assume $m_2=4\mathrm{.}00kg.)$

vec$(g{)}_{\text{n}\text{e}\text{t}}=$

$$

If the two masses are unequal, what is the net contribution to the field from each mass in the two perpendicular directions? $\frac{m}{s^2}$