Two floating point numbers are added to form a floating$-$point sum: $($F$\_1\backslash$times $2^$E$\_1)+($F$\_2\backslash$times $2^$E$\_2)=$F $\backslash$times $2^$E Assume that F$\_1$ and F$\_2$ are normalised and that the result should be normalised. $($i$)$ Illustrate the steps required to carry out floating$-$point addition for F$\_1=1\mathrm{.}0101,$ E$\_1=1001$ and F$\_2=0\mathrm{.}1010,$ E$\_2=1000.$ Note that the fractions are $5$ bits, including sign, and the exponents are $4$ bits, including sign. $($ii$)$ Verify the result of the addition in part b$)($i$).$