Question: Two horizontal forces, P and , are acting on a block that is placed on a table. We know that P = (2.101 +4.25k)N

Two horizontal forces, P and , are acting on a block that

 

Two horizontal forces, P and , are acting on a block that is placed on a table. We know that P = (2.101 +4.25k)N but the magnitude and direction of are unknown. The block moves along the table. Assume there is no friction between the object and the table. Here the mass of the block is 4.75 kg. (a) Determine the force Q when the block moves with constant velocity. Express your answer in vector form. 0 = (b) Determine the force Q when the acceleration of the block is (-2.50 +2.25km/s. Express your answer in vector form. Q N The acceleration given here is due to the net force acting on the object. N (c) Determine the force Q when the acceleration of the block is (2.50 -2.25k)m/s. Express your answer in vector form. Q= How does the change in the sign of the acceleration affect the value of Q? N

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!