Two identical charges, -6.0 nC each, are fixed 1.0 m apart. An electron is released from rest near the midpoint between the charges, as shown in the diagram. After travelling a distance of 1.2 m, the electron's speed is equal to -6 nCo 50 cm V 1.2 m 50 cm 6nce /1 O a. 6.8 x 10 m/s b. 3.4 x 10 m/s O c. 4.8 x 10 m/s O d. 8.7 x 10 m/s O e. 5.4 x 10 m/sConsider the system of charges shown in the diagram, where Q = 8.0 nC. The electric potential at point P is equal to o+ Q 3.0 m Q P +Q 6.0 m + 3.0m - O a. 36 V O b. 14 V O c. 24 V O d. 60 V O e. 12 VThe system shown in the diagram is in static equilibrium, where the hanging 40-g bead carries a positive charge of Q = 1.0 AC. The other bead is located 20 cm to the left of the hanging bead and carries a negative charge of -Q. The thread makes an angle (0) with the vertical equal to 20 cm- Q /1 mark K a. 350 b. 550 c. 110 d. 60 O e. 30