Two objects, $m_1$ and $m_2$ are placed a beginning distance $d$ from each other and have a force of $10$ N between them. What will be the new force between them based on the following changes:

a$.$ The distance is cut in half. $Fg=2\frac{1}{(\frac{1}{2}{)}^2}=4*Fy=40N$

b$.$ The distance is doubled. $100$ N

c$.$ the mass of $m_1$ is doubled.

d$.$ The mass of $m_1$ is double, the mass of $m_2$ is tripled, and the distance is made $3$ times greater.