Two particles of equal mass m go round a circle of diameter R under the action...

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Two particles of equal mass m go round a circle of diameter R under the action of their mutual gravitational attraction. The speed of each particle is :- (1) V = 2 (2) V (3) V= (4) V = 2R √ Gm Gm 2R Gm 2V R 4Gm R Two particles of equal mass m go round a circle of diameter R under the action of their mutual gravitational attraction. The speed of each particle is :- (1) V = 2 (2) V (3) V= (4) V = 2R √ Gm Gm 2R Gm 2V R 4Gm R

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The detailed answer for the above question is provided below The correct answer is option 2 V Gm2R T... View the full answer