Question: Two planes given by equations 4x + 3y - 5z = 5 and 2x-y + 3z = 5 intersect in a space along a

Two planes given by equations 4x + 3y - 5z = 5

 

Two planes given by equations 4x + 3y - 5z = 5 and 2x-y + 3z = 5 intersect in a space along a line. Find equation of that line. three-dimensional (b) Find the shortest distance between the two planes 4x + 3y - 5z = 8 and 3y + 4x + 5z + 12 = 0. [10 marks] [10 marks]

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Sob a Given 4x 3452 5 2 1 54x3901 2xy375 Z 5 2x y Equating and E 2 54738 520y 975y ... View full answer

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